48x^2-56x=0

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Solution for 48x^2-56x=0 equation:



48x^2-56x=0
a = 48; b = -56; c = 0;
Δ = b2-4ac
Δ = -562-4·48·0
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-56}{2*48}=\frac{0}{96} =0 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+56}{2*48}=\frac{112}{96} =1+1/6 $

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